Developer forum

You cannot with rows. They depend on their row definition that is setup on a layout.

But you can render the grid (all rows) from one page on another using @RenderGrid in your viewmodel templates, i.e. a layout template using pageviewmodel or a productListViewModel template from the product catalog from viewmodels app.

RenderGrid takes a pageid as an argument - so you need a page for each piece of content - one or more rows.

Be careful of performance. Cannot guarentee anything if you call this many times on a page.

BR Nicolai

Hi Nicolai,

That's even better.

That's how I was planning it. One page per request.

What if I have a Page using VisualEditor and one of the columns will have a ProductCatalog in it and I am planning on inserting this Row into the ProductsRender.cshtml template?

This will be inserted only in top-level category pages, I expect it to be cached but we'll see how it will handle it.

I can also try and load it async if performance will be an issue.

Thank you,

Adrian

You should be able to do that. Try it!

Hi Nicolai,

I have tried using RenderGrig(<pageId>) but it only works on the ContentPage template.

As you mentioned, ViewModel templates only.

I am not using the productListViewModel template yet for my ProductList and therefore I cannot use this approach in ProductRender or in product list blocks.

I cannot use it in ContentPage either because I don't have access to Group properties there.

Apart from the option of switching to productListViewModels, what other option do I have if I want to enrich the ProductList page with VisualEditor managed content?

Thank you,

Adrian

Custom code...

Hi Nicolai,

That's obviously gonna be custom code. I have no doubt about it.

But I can be done in a couple of ways and I was wondering which approach would be the most efficient one.

To put it simply, how would you do it?

Thank you,

Adrian