Developer forum

Hi Adrian

An item in the item publisher is either a page or a paragraph.

In the template, figure out if the current item you are rendering is a page or paragraph, then load the instance of that object - (Dynamicweb.Content.Services.Pages/Paragraphs) - and then call  Dynamicweb.Frontend.ContentViewModelFactory.CreatePageInfoViewModel/CreateParagraphViewModel respectively to get a viewmodel of the page or paragraph - both of them having an Item property contining the image property of the right viewmodel.

Dummy code:

@{
    // Get Page and Paragraph IDs from item fields
    var pageId = GetInteger("ItemPublisher:Item.Field.PageId");
    var paragraphId = GetInteger("ItemPublisher:Item.Field.ParagraphId");

    PageInfoViewModel pageModel = null;
    ParagraphViewModel paragraphModel = null;

    if (paragraphId > 0)
    {
        // It's a paragraph
        var paragraph = ParagraphService.Instance.GetParagraph(paragraphId);
        paragraphModel = ContentViewModelFactory.CreateParagraphViewModel(paragraph);
    }
    else if (pageId > 0)
    {
        // It's a page
        var page = PageService.Instance.GetPage(pageId);
        pageModel = ContentViewModelFactory.CreatePageInfoViewModel(page);
    }

    // Access image from the Item fields in the ViewModel
    var imagePath = paragraphModel?.Item?.GetFile("Image")?.Path 
                    ?? pageModel?.Item?.GetFile("Image")?.Path;
}

BR Niolai

Hi Nicolai,

Thank you, that is very useful.
I have tried first identifying the Item: GetItemById(string ItemType, string ItemId)
In this case, the ContentViewModelFactory.CreateItemViewModel is internal and I could not use it.

Going through the PageViewModel approach may work easier.
Thank you,

Adrian