I have a quick question here, couldn't find it here nut hoped that someone could have discussed the issue.
What I need is a little xslt snippet I can use in Breadcrumb xslt file.
As I have a breadcrumb, all I want is to have the last element (current page) not be a link. Instead just a plain text.
I have this script, but it does not seam to parse...
<xsl:template match="//Page">
<xsl:param name="depth"/>
<img src="Files/Templates/Designs/Conclusion/img/BreadcrumbPil.png" class="breadcrumbDevider" alt="" />
<xsl:when test="@Active='True'">
<xsl:value-of select="@MenuText" disable-output-escaping="yes"/>
</xsl:when>
<xsl:otherwise>
<a><xsl:attribute name="href"><xsl:value-of select="@FriendlyHref" disable-output-escaping="yes"/></xsl:attribute>
<xsl:value-of select="@MenuText" disable-output-escaping="yes"/>
</a>
</xsl:otherwise>
<xsl:if test="count(Page)">
<span class="B{@AbsoluteLevel}">
<xsl:apply-templates select="Page">
<xsl:with-param name="depth" select="$depth+1"/>
</xsl:apply-templates>
</span>
</xsl:if>
</xsl:template>
Some small xslt snippets that could help me with this one would be more than appreciated!
Kind regards,
Dmitrij