Render page content in DW9.19

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Adrian Ursu

Posted on 27/02/2026 12:43:37

Hi guys,
I am trying to export some pages (blog articles), including the HTML markup.
I know that I can export using RenderGrid for pages based on the Visual editor, but I also have some pages that are not based on the Visual editor.
To make things even worse, the pages are basedon the old Rapido DynamicArticle layout.

Now, is there any method in this new API that would allow me to render the page content using a specific template?

Thank you,
Adrian

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Adrian Ursu

Posted on 08/03/2026 09:51:58

Anybody?

Nicolai Pedersen

Posted on 09/03/2026 10:42:57

Hi Adrian

You can try this:

using (PageViewIsolation pvIso = new PageViewIsolation(intPageID, false, true))
{
    PageView PageView = PageView.Current();
    PageView.Redirect = false;
    PageView.IsEmailContext = true;
    PageView.Context = pageviewContext;

    if (!string.IsNullOrEmpty(template))
    {
        //TODO: Why something this old in something that new....
        //Dim tm As New Dynamicweb.Frontend.Templates()
        //tm.TemplateFile = template
        //PageView.Template = tm
    }

    return PageView.Output();
}

Then you got the page. Then if you only want part of the page, you can use some regex magic to clip that parts you want.

Adrian Ursu

Posted on 09/03/2026 10:45:56

Great!

I will try it out and come back with a status.
Thank you,
Adrian

Adrian Ursu

Posted on 09/03/2026 13:00:28

Hi Nicolai,
It does not seem to work. There is a missing pageviewContext, which I need for each page I want to render, and a PageView.Template only supports "get" without "set".
I will find another solution.

Thank you,
Adrian

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Render page content in DW9.19

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