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Hi there,

You could use a separate XSLT file for the Footer menu and filter out the item by its ID.

Imar

Hi Joachim,

You can use Test in XSLT, could be done like this: (if the ID is "1").

That works perfectly! Thanks alot.

Im very sorry, but im all new to xslt, and i have some very basical questions.

How do you use "mode" expand:all? Now i only gets the level 1 item's

Here is my code:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"  xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >

  <xsl:output method="xml" omit-xml-declaration="yes" indent="yes"  encoding="utf-8" />
  <xsl:param name="html-content-type" />
  <xsl:template match="/NavigationTree">
    <ul class="M0">
      <xsl:apply-templates select="Page">
       
      </xsl:apply-templates>
    </ul>

  </xsl:template>

  <xsl:template match="Page">
    <li class="{@class}">
        <xsl:choose>
          <xsl:when test="@ID!='6'">
            <a class="{@class}">
              <xsl:attribute name="href">
                <xsl:value-of select="@FriendlyHref" disable-output-escaping="yes"/>
              </xsl:attribute>
              <xsl:value-of select="@MenuText" disable-output-escaping="yes"/>
            </a>
          </xsl:when>
        </xsl:choose>
    </li>
  </xsl:template>

</xsl:stylesheet>

Take a look at the file LIClean.xslt from the /Files/Templates/Navigation folder.

It recursively builds up the menu by calling <xsl:apply-templates select="Page"> again. You may want to use this file as your starting point as it's one the cleaner XSLT files for navigation.

Hope this helps,

Imar

Works perfectly, and as intended now.
Thanks for the help both of you!

- Joachim